已知x+y=5,xy=-6求（2x-3y-2xy)-(x-4y+xy)的值?

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已知x+y=5,xy=-6求（2x-3y-2xy)-(x-4y+xy)的值?
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已知x+y=5,xy=-6求（2x-3y-2xy)-(x-4y+xy)的值?
已知x+y=5,xy=-6求（2x-3y-2xy)-(x-4y+xy)的值?

已知x+y=5,xy=-6求（2x-3y-2xy)-(x-4y+xy)的值?
（2x-3y-2xy）-（x-4y+xy）
=2x-3y-2xy-x+4y-xy
=（2-1)x+(-3+4)y+(-2-1)xy
=x+y-3xy
因为x+y=5,xy=-6
所以原式=5+18=23

(2x-3y-2xy)-(x-4y+xy)
=2x-3y-2xy-x+4y-xy
=x+y-3xy
=5+18
=23

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