(1+sin4a-cos4a)/(1+sin4a+cos4a)的值=?(化到最简)(1+cosa-sina)/(1-cosa-sina) + (1-cosa-sina)/(1+cosa-sina)
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![(1+sin4a-cos4a)/(1+sin4a+cos4a)的值=?(化到最简)(1+cosa-sina)/(1-cosa-sina) + (1-cosa-sina)/(1+cosa-sina)](/uploads/image/z/758741-5-1.jpg?t=%281%2Bsin4a-cos4a%29%2F%281%2Bsin4a%2Bcos4a%29%E7%9A%84%E5%80%BC%3D%3F%EF%BC%88%E5%8C%96%E5%88%B0%E6%9C%80%E7%AE%80%EF%BC%89%281%2Bcosa-sina%29%2F%281-cosa-sina%29+%2B+%281-cosa-sina%29%2F%281%2Bcosa-sina%29)
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(1+sin4a-cos4a)/(1+sin4a+cos4a)的值=?(化到最简)(1+cosa-sina)/(1-cosa-sina) + (1-cosa-sina)/(1+cosa-sina)
(1+sin4a-cos4a)/(1+sin4a+cos4a)的值=?(化到最简)
(1+cosa-sina)/(1-cosa-sina) + (1-cosa-sina)/(1+cosa-sina)
(1+sin4a-cos4a)/(1+sin4a+cos4a)的值=?(化到最简)(1+cosa-sina)/(1-cosa-sina) + (1-cosa-sina)/(1+cosa-sina)
把sin4a,cos4a 用二倍角公式
1=(sin4a)^2+(cos4a)^2得
(2(sin2a)^2+2sin2acos2a)/(2(cos2a)^2+2sin2acos2a)
=((tan2a)^2+tan2a)/(1+tan2a)
=tan2a
把a=2*(a/2)用上面的方法做的结果是1/(sin(a/2)*cos(a/2))