作业帮解方程2sin3x·cos2x+2sin^2x=0
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解方程2sin3x·cos2x+2sin^2x=0
解方程2sin3x·cos2x+2sin^2x=0
解方程2sin3x·cos2x+2sin^2x=0
2*(sin(x))^3*cos(2*x)+2*(sin(x))^2=0
解析：左式= 2*(sin(x))^3*(1-2(sin(x))^2)+2*(sin(x))^2
= 2*(sin(x))^3-4*(sin(x))^5+2*(sin(x))^2
= [sin(x)-2*(sin(x))^3+1]2*(sin(x))^2
=(sin(x)-1)*(-2*(sin(x))^2-2*sin(x)-1)*2*(sin(x))^2=0
∵-2*(sin(x))^2-2*sin(x)-1<0
∴sinx=1==>x1=2kπ+π/2
Sinx=0==>x2=2kπ,x3=2kπ+π
解方程2sin3x·cos2x+2sin^2x=0
解方程2sin3x·cos2x+2sin^2x=0
解三角方程2sin3x·cos2x+2sin^2x=0
解三角方程2sin3x*cos2x+2sin^2(x)=0
高中的三角解方程 ..解下列方程:..)1.sin3x=sin(/5)2.(tanx)^2=1/31.sin3x=sin(π/5)忘了打π
sin^2x+cos2x=1解方程 求过程
解方程；SinX+Sin2X+Sin3X = 1+CosX+Cos2X.
sin3x+cosx-cos3x-sinx/2(sin2x+cos2x)化简
sin3x+cosx-cos3x-sinx/2(sin2x+cos2x)化简
解方程:(sin2x+cos2x)/(1-sin^2x-2cos2x)=2X属于(π/2,π）
sin2x=sin(x-派/3)和cos(2x-派/6)=sin(3x-派/3)和sin5x=sin3x这种方程怎么解啊
|sin3x|=sin|3x| 还有|2sin3x|大于等于1
|sin3x|=sin|3x| 还有|2sin3x|大于等于1
sinx+sin3x+sin5x+.sin(2n-1)/cosx+cos3x+cos5x+.cos(2n-1)= sin2x+sin4x+.sin 2nx /cos2xsinx+sin3x+sin5x+.sin(2n-1)/cosx+cos3x+cos5x+.cos(2n-1)=sin2x+sin4x+.sin 2nx /cos2x+cos4x+.cos2nx =已知数列an通项公式（n+2）*（9/10）的n次方,求n为何
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