U={1,2},A={X|X²+PX+Q=0},CuA={1},则P+Q=_____
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/27 06:58:46
![U={1,2},A={X|X²+PX+Q=0},CuA={1},则P+Q=_____](/uploads/image/z/7620898-58-8.jpg?t=U%3D%7B1%2C2%7D%2CA%3D%7BX%7CX%26%23178%3B%2BPX%2BQ%3D0%7D%2CCuA%3D%7B1%7D%2C%E5%88%99P%2BQ%3D_____)
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U={1,2},A={X|X²+PX+Q=0},CuA={1},则P+Q=_____
U={1,2},A={X|X²+PX+Q=0},CuA={1},则P+Q=_____
U={1,2},A={X|X²+PX+Q=0},CuA={1},则P+Q=_____
两个方程解决一个是P²-4Q=0,另一个是把2带入得4+2P+Q=0