如图,等腰三角形ABC的顶角∠A=36°.⊙O和底边BC相切于BC的中点D,并于两腰相交于E,F,G,H四点,其中点G,F分别是两腰AB,AC的中点.求证:五边形DEFGH是正五边形 问为什么因为BC是切线就∠BDH=∠CDE=36°?
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![如图,等腰三角形ABC的顶角∠A=36°.⊙O和底边BC相切于BC的中点D,并于两腰相交于E,F,G,H四点,其中点G,F分别是两腰AB,AC的中点.求证:五边形DEFGH是正五边形 问为什么因为BC是切线就∠BDH=∠CDE=36°?](/uploads/image/z/7622827-43-7.jpg?t=%E5%A6%82%E5%9B%BE%2C%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E9%A1%B6%E8%A7%92%E2%88%A0A%3D36%C2%B0.%E2%8A%99O%E5%92%8C%E5%BA%95%E8%BE%B9BC%E7%9B%B8%E5%88%87%E4%BA%8EBC%E7%9A%84%E4%B8%AD%E7%82%B9D%2C%E5%B9%B6%E4%BA%8E%E4%B8%A4%E8%85%B0%E7%9B%B8%E4%BA%A4%E4%BA%8EE%2CF%2CG%2CH%E5%9B%9B%E7%82%B9%2C%E5%85%B6%E4%B8%AD%E7%82%B9G%2CF%E5%88%86%E5%88%AB%E6%98%AF%E4%B8%A4%E8%85%B0AB%2CAC%E7%9A%84%E4%B8%AD%E7%82%B9.%E6%B1%82%E8%AF%81%EF%BC%9A%E4%BA%94%E8%BE%B9%E5%BD%A2DEFGH%E6%98%AF%E6%AD%A3%E4%BA%94%E8%BE%B9%E5%BD%A2+%E9%97%AE%E4%B8%BA%E4%BB%80%E4%B9%88%E5%9B%A0%E4%B8%BABC%E6%98%AF%E5%88%87%E7%BA%BF%E5%B0%B1%E2%88%A0BDH%3D%E2%88%A0CDE%3D36%C2%B0%3F)
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