(1).已知 如图1,在△ABC中,∠BAC=90°,AB=AC,BE平分∠ABC,交AC于D,CE⊥BE.求证:CE=1/2BD(2.)如图2,∠CAB与∠EBC的角平分线交于O求证:CO平分∠BCF
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![(1).已知 如图1,在△ABC中,∠BAC=90°,AB=AC,BE平分∠ABC,交AC于D,CE⊥BE.求证:CE=1/2BD(2.)如图2,∠CAB与∠EBC的角平分线交于O求证:CO平分∠BCF](/uploads/image/z/7626218-50-8.jpg?t=%EF%BC%881%EF%BC%89.%E5%B7%B2%E7%9F%A5+%E5%A6%82%E5%9B%BE1%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0BAC%3D90%C2%B0%2CAB%3DAC%2CBE%E5%B9%B3%E5%88%86%E2%88%A0ABC%2C%E4%BA%A4AC%E4%BA%8ED%2CCE%E2%8A%A5BE.%E6%B1%82%E8%AF%81%EF%BC%9ACE%3D1%2F2BD%EF%BC%882.%EF%BC%89%E5%A6%82%E5%9B%BE2%2C%E2%88%A0CAB%E4%B8%8E%E2%88%A0EBC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4%E4%BA%8EO%E6%B1%82%E8%AF%81%EF%BC%9ACO%E5%B9%B3%E5%88%86%E2%88%A0BCF)
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