作业帮已知1
来源：学生作业帮助网 编辑：作业帮 时间：2024/09/08 19:48:46
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已知1 已知1 1 1
已知1
x>1
x-1>0
所以 |x-1|=x-1
x<3
x-3<0
所以 |x-3|=-（x-3)
所以原式=(x-1)/(x-1)+[-(x-3)]/(x-3)
=1-1
=0
所以：|x-1|=x-1,|x-3|=-(x-3)
丨x-1丨/x-1+丨x-3丨/x-3
=(x-1)/(x-1)-(x-3)/(x-3)
=1-1
=0
x-3<0
丨x-1丨/(x-1)+丨x-3丨/(x-3)
=(x-1)/(x-1)+(3-x)/(x-3)
=(x-1)/(x-1)-(x-3)/(x-3)
=1-1
=0