f(x)=根号3sin(2x-π/6)+2sin^2(x-π/12),若x∈[-π/2,π/2],求f(x)的值域帮个忙,
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/29 07:25:37
![f(x)=根号3sin(2x-π/6)+2sin^2(x-π/12),若x∈[-π/2,π/2],求f(x)的值域帮个忙,](/uploads/image/z/7629197-5-7.jpg?t=f%28x%29%3D%E6%A0%B9%E5%8F%B73sin%282x-%CF%80%2F6%29%2B2sin%5E2%28x-%CF%80%2F12%29%2C%E8%8B%A5x%E2%88%88%5B-%CF%80%2F2%2C%CF%80%2F2%5D%2C%E6%B1%82f%28x%29%E7%9A%84%E5%80%BC%E5%9F%9F%E5%B8%AE%E4%B8%AA%E5%BF%99%2C)
x)KӨд}`řyF48#
0HSEҊG y
{ΟtǺ';V=?S&HfMD@Ά1`#k`*uC"#d Y#d %4= 21IdC*u!2`1_\g
\ Pڊ
f(x)=根号3sin(2x-π/6)+2sin^2(x-π/12),若x∈[-π/2,π/2],求f(x)的值域帮个忙,
f(x)=根号3sin(2x-π/6)+2sin^2(x-π/12),若x∈[-π/2,π/2],求f(x)的值域
帮个忙,
f(x)=根号3sin(2x-π/6)+2sin^2(x-π/12),若x∈[-π/2,π/2],求f(x)的值域帮个忙,
f(x)=√3sin(2x-π/6)+2sin²(x-π/12)
=√3sin(2x-π/6)-cos(2x-π/6)-1
=2sin(2x-π/6)cos(π/6)-2cos(2x-π/6)sin(π/6)-1
=2sin(2x-π/3)-1
x∈[-π/2,π/2]
2x-π/6∈[-4π/3,2π/3]
sin(2x-π/3)∈[-1,1]
y∈[-3,1]
已知F(X)=根号3COS^2 X+SIN XCOS X-2SIN X*SIN(X-π/6),求F(X)的最大值
已知函数f(x)=2根号3sin平方x-sin(2x-π/3)
化简F(X)=2COSXCOSX(π/6-X)-根号3SIN^2X+SINXCOSX
f(x)=根号3sin(2x-π/6)+2sin^2(x-π/12)求单调递增区间
函数f(x)=根号3sinωx+cosωx(ω>0)怎样变为f(x)=2sin(ωx+π/6)
f(x)=2sin^2(π/4+x)+根号3(sin^2x+cos^2x)f(x)=2sin^2(π/4+x)+根号3(sin^2x-cos^2x) 符号打错了
求函数f(x)=2sin(π-x)sin(π/2-x)+2根号3sin^2x-根号3的单调递减区间
已知函数f(x)=-根号3sin²x+sinxcosx,求f(25π/6)
已知向量a=(根号2sin(4/π+x)+1,-根号3),b=(根号2sin(4/π+x)-1,cos2x函数f(x)=ab (1)若函数h(x)=f(x+t)已知向量a=(根号2sin(4/π+x)+1,-根号3),b=(根号2sin(4/π+x)-1,cos2x函数f(x)=ab(1)若函数h(x)=f(x+t)的图像关于(-6/π,0)对
f(x)=1+2sin(2x+π/6),若f(x)=1-根号3,且x∈[-π/3,π/3]求x?
f(x)=2根号3sin^2x-sin(2x-π/3)若x属【-π/2,0】,求函数f(x)的最大值
已知函数f(x)=[2sin(x+π/3)+sinx]cosx-根号3sin^2x,x属于R,求函数f(x)最小正周期
已知函数f(x)=[2sin(x+π/3)+sinx]cosx-根号3sin^2x,x属于R,求函数f(x)最小正周期
f(x)=2sin^2x+根号3sin2x+α,且|f(x)|
f(x)=1+sin(2x)-根号3 cos2x,|f(x)-m|
f(x)=1+sin(2x)-根号3 cos2x |f(x)-m|
函数f(x)=负根号3sin ^2x+sin x cos x f(a/2)=1/4-根号3/2求sin a值
f(x)=2cosx*sin(x+π/3)-根号3/2 怎么化简?