(1+y^2)dx-(1+x^2)dy=0的通解
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(1+y^2)dx-(1+x^2)dy=0的通解
(1+y^2)dx-(1+x^2)dy=0的通解
(1+y^2)dx-(1+x^2)dy=0的通解
(1+y^2)dx-(1+x^2)dy=0
(1+y^2)dx=(1+x^2)dy
dx/(1+x^2)=dy/(1+y^2)
两边积分
arctanx=arctany+C
(1+y^2)dx-(1+x^2)dy=0
(1+y^2)dx=(1+x^2)dy
1/(1+x^2)dx=1/(1+y^2)dy
arctanx=arctany+c
dy/dx,y=(1+x+x^2)e^x
dy/dx=x(1+y^2)/y通解
dy/dx=(e^x+x)(1+y^2)通解
(x^2)dy+(y^2)dx=dx-dy
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