已知(x-3)/(x+1)(x-1)=A/(x+1)+B/(x-1) 求整数A、B的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/06/29 22:22:51
已知(x-3)/(x+1)(x-1)=A/(x+1)+B/(x-1) 求整数A、B的值
x){}K5*t55* 5LCM[GGIWx-Ϧnp||Vӆ=6IE/ P FHFU)(Ustb0$l$=@K0LU@[!1P5F`qG[,' m @!7R

已知(x-3)/(x+1)(x-1)=A/(x+1)+B/(x-1) 求整数A、B的值
已知(x-3)/(x+1)(x-1)=A/(x+1)+B/(x-1) 求整数A、B的值

已知(x-3)/(x+1)(x-1)=A/(x+1)+B/(x-1) 求整数A、B的值
1/(x+1) - 1/(x-1) = -2/(x+1)(x-1)
(x-3)/(x+1)(x-1)
= [(x-1)-2] / (x+1)(x-1)
= (x-1)/(x+1)(x-1) - 2/(x+1)(x-1)
= 1/(x+1) + [1/(x+1) - 1/(x-1)]
= 2/(x+1) - 1/(x-1)
A = 2
B = -1