x=2y,2x-y+z=2,x-2y+3z=-3
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x=2y,2x-y+z=2,x-2y+3z=-3
x=2y,2x-y+z=2,x-2y+3z=-3
x=2y,2x-y+z=2,x-2y+3z=-3
x=2y ①
2x-y+z=2 ②
x-2y+3z=-3③
①分别代人②、③得
4y-y+z=2即3y+z=2 ④
2y-2y+3z=-3即z=-1
z=-1代人④得
3y-1=2
y=1
代人①得
x=2
所以方程组的解为
x=2
y=1
z=-1
x=2,y=1,z=-1
x=2
y=1
z=-1
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