数列｛an｝满足a1=1,an=1/2a(n-1)1(n≥2)（1）若bn=an-2,求证｛bn｝为等比数列（2）求｛an｝的通项公式更正：将“n=1/2a(n-1)1”改为“an=1/2a(n-1)+1”

数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 数列{an}满足a1=a,an+1=1+1/an.若3/2 数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 数列[An]满足a1=2,a（n+1）=3an-2 求an 数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式 数列{an}满足a1=1 an+1=2n+1an/an+2n 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 数列an满足a1=2,an+1=4an+9,则an=? 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 数列an满足a1=2,an+1=an²求an 数列an满足a1=2,an+1=an²求an 已知数列an满足条件a1=-2 a（n+1）=2an/(1-an) 则an= 已知数列an满足a1=1,a(n+1)=an/(3an+2),则an=? 数列{an}满足a1=2,a(n+1)=-1/(an+1),则a2010等于 数列｛an｝满足a1=3,a n+1=2an,则a4等于 已知数列{an}满足a(n+1)=an+n,a1=1,则an= 已知数列{an}满足a(n+1)=an+lg2,a1=1,求an