已知(4a+1)的平方+l2b-a-4/3l=0化简求出(3a-5b)-3(5a-7b+1)+(2a+7b-1)的解 答案我知道是-7/4已知(4a+1)的平方+l2b-a-四分之三l=0化简求出4(3a-5b)-3(5a-7b+1)+(2a+7b-1)的解
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![已知(4a+1)的平方+l2b-a-4/3l=0化简求出(3a-5b)-3(5a-7b+1)+(2a+7b-1)的解 答案我知道是-7/4已知(4a+1)的平方+l2b-a-四分之三l=0化简求出4(3a-5b)-3(5a-7b+1)+(2a+7b-1)的解](/uploads/image/z/765106-34-6.jpg?t=%E5%B7%B2%E7%9F%A5%284a%2B1%29%E7%9A%84%E5%B9%B3%E6%96%B9%2Bl2b-a-4%2F3l%3D0%E5%8C%96%E7%AE%80%E6%B1%82%E5%87%BA%283a-5b%29-3%285a-7b%2B1%29%2B%EF%BC%882a%2B7b-1%EF%BC%89%E7%9A%84%E8%A7%A3+%E7%AD%94%E6%A1%88%E6%88%91%E7%9F%A5%E9%81%93%E6%98%AF-7%2F4%E5%B7%B2%E7%9F%A5%284a%2B1%29%E7%9A%84%E5%B9%B3%E6%96%B9%2Bl2b-a-%E5%9B%9B%E5%88%86%E4%B9%8B%E4%B8%89l%3D0%E5%8C%96%E7%AE%80%E6%B1%82%E5%87%BA4%283a-5b%29-3%285a-7b%2B1%29%2B%EF%BC%882a%2B7b-1%EF%BC%89%E7%9A%84%E8%A7%A3)
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