作业帮[（-3ab）²×a³+2a³×（-3ab）³×1/2b]÷（3a²b²）² ,其中a=1/3,b=-b=-(1/2)
来源：学生作业帮助网 编辑：作业帮 时间：2024/08/07 04:50:19
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[（-3ab）²×a³+2a³×（-3ab）³×1/2b]÷（3a²b²）² ,其中a=1/3,b=-b=-(1/2)
[（-3ab）²×a³+2a³×（-3ab）³×1/2b]÷（3a²b²）² ,其中a=1/3,b=-
b=-(1/2)
[（-3ab）²×a³+2a³×（-3ab）³×1/2b]÷（3a²b²）² ,其中a=1/3,b=-b=-(1/2)
[（-3ab）²×a³+2a³×（-3ab）³×1/2b]÷（3a²b²）²
=[-3a^5b^2-3a^6b^2]÷9a^4b^4
=-a/3b^2-a^2/3b^2
=-a/3b^2*(a-1)
=-a/3b^2*0
=0