∫根号(x^2-4)dx用换元积分法算出来令x=2csct,我算到的答案是(x/2)根号(x^2-4)+2ln|x/2-(1/2)根号x^2-4|+C,跟书本答案不同
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![∫根号(x^2-4)dx用换元积分法算出来令x=2csct,我算到的答案是(x/2)根号(x^2-4)+2ln|x/2-(1/2)根号x^2-4|+C,跟书本答案不同](/uploads/image/z/7654018-58-8.jpg?t=%E2%88%AB%E6%A0%B9%E5%8F%B7%EF%BC%88x%5E2-4%29dx%E7%94%A8%E6%8D%A2%E5%85%83%E7%A7%AF%E5%88%86%E6%B3%95%E7%AE%97%E5%87%BA%E6%9D%A5%E4%BB%A4x%3D2csct%2C%E6%88%91%E7%AE%97%E5%88%B0%E7%9A%84%E7%AD%94%E6%A1%88%E6%98%AF%28x%2F2%29%E6%A0%B9%E5%8F%B7%EF%BC%88x%5E2-4%EF%BC%89%2B2ln%7Cx%2F2-%281%2F2%29%E6%A0%B9%E5%8F%B7x%5E2-4%7C%2BC%2C%E8%B7%9F%E4%B9%A6%E6%9C%AC%E7%AD%94%E6%A1%88%E4%B8%8D%E5%90%8C)
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