已知a=(1-t,2t-1,0),b=(2,t,t),则|b-a|的最小值是() (A)根号5 (B)根号6 (C)根号2 (D)根号
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![已知a=(1-t,2t-1,0),b=(2,t,t),则|b-a|的最小值是() (A)根号5 (B)根号6 (C)根号2 (D)根号](/uploads/image/z/7657195-67-5.jpg?t=%E5%B7%B2%E7%9F%A5a%3D%281-t%2C2t-1%2C0%29%2Cb%3D%282%2Ct%2Ct%EF%BC%89%2C%E5%88%99%EF%BD%9Cb%EF%BC%8Da%EF%BD%9C%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E6%98%AF%EF%BC%88%EF%BC%89+%EF%BC%88A%EF%BC%89%E6%A0%B9%E5%8F%B75+%EF%BC%88B%EF%BC%89%E6%A0%B9%E5%8F%B76+%EF%BC%88C%29%E6%A0%B9%E5%8F%B72+%EF%BC%88D%EF%BC%89%E6%A0%B9%E5%8F%B7)
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已知a=(1-t,2t-1,0),b=(2,t,t),则|b-a|的最小值是() (A)根号5 (B)根号6 (C)根号2 (D)根号
已知a=(1-t,2t-1,0),b=(2,t,t),则|b-a|的最小值是() (A)根号5 (B)根号6 (C)根号2 (D)根号
已知a=(1-t,2t-1,0),b=(2,t,t),则|b-a|的最小值是() (A)根号5 (B)根号6 (C)根号2 (D)根号
|b-a|=根号[(2-(1-t))^2+(t-(2t-1))^2+(t-0)^2]=根号(t^2+2)
当t=0时,有最小值,最小值为根号2
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选c