一道初三计算 (mx-n)^2-n^2=0(m不等0) (b^2+1)x^2-2bx+b^2+4=0
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![一道初三计算 (mx-n)^2-n^2=0(m不等0) (b^2+1)x^2-2bx+b^2+4=0](/uploads/image/z/7657635-3-5.jpg?t=%E4%B8%80%E9%81%93%E5%88%9D%E4%B8%89%E8%AE%A1%E7%AE%97+%28mx-n%29%5E2-n%5E2%3D0%EF%BC%88m%E4%B8%8D%E7%AD%890%EF%BC%89+%EF%BC%88b%5E2%2B1%29x%5E2-2bx%2Bb%5E2%2B4%3D0)
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一道初三计算 (mx-n)^2-n^2=0(m不等0) (b^2+1)x^2-2bx+b^2+4=0
一道初三计算 (mx-n)^2-n^2=0(m不等0) (b^2+1)x^2-2bx+b^2+4=0
一道初三计算 (mx-n)^2-n^2=0(m不等0) (b^2+1)x^2-2bx+b^2+4=0
就是a^2-b^2=(a-b)*(a+b);
x=0;x=2n/m;
用求根公式就行...