数学天才进〜已知:点D是角ABC和角ACB的外角平分线的交点,DE平行于BM,交AB于E,交AC于E,求证:EF=BE-CF
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![数学天才进〜已知:点D是角ABC和角ACB的外角平分线的交点,DE平行于BM,交AB于E,交AC于E,求证:EF=BE-CF](/uploads/image/z/7661115-27-5.jpg?t=%E6%95%B0%E5%AD%A6%E5%A4%A9%E6%89%8D%E8%BF%9B%26%2312316%3B%E5%B7%B2%E7%9F%A5%EF%BC%9A%E7%82%B9D%E6%98%AF%E8%A7%92ABC%E5%92%8C%E8%A7%92ACB%E7%9A%84%E5%A4%96%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%E7%9A%84%E4%BA%A4%E7%82%B9%2CDE%E5%B9%B3%E8%A1%8C%E4%BA%8EBM%2C%E4%BA%A4AB%E4%BA%8EE%2C%E4%BA%A4AC%E4%BA%8EE%2C%E6%B1%82%E8%AF%81%EF%BC%9AEF%3DBE-CF)
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