已知向量A=(cosa,sina) ,向量B=(cosb,sinb)求证:(A+B)⊥(A-B)若-π/4<α<π/4,β =π/4,且A×B=3/5,求sinα的值
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![已知向量A=(cosa,sina) ,向量B=(cosb,sinb)求证:(A+B)⊥(A-B)若-π/4<α<π/4,β =π/4,且A×B=3/5,求sinα的值](/uploads/image/z/766619-35-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8FA%3D%28cosa%2Csina%29+%2C%E5%90%91%E9%87%8FB%3D%28cosb%2Csinb%29%E6%B1%82%E8%AF%81%EF%BC%9A%EF%BC%88A%2BB%EF%BC%89%E2%8A%A5%28A-B%29%E8%8B%A5-%CF%80%2F4%EF%BC%9C%CE%B1%EF%BC%9C%CF%80%2F4%2C%CE%B2+%3D%CF%80%2F4%2C%E4%B8%94A%C3%97B%3D3%2F5%2C%E6%B1%82sin%CE%B1%E7%9A%84%E5%80%BC)
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