一道等比数列题已知 A1=2,A2=3,{An*An+1}为公比为q=3的等比数列,设 Bn=A2n-1+A2n n为整整数,求证{Bn}为等比数列说明 n n+1 2n-1 2n 为下标
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![一道等比数列题已知 A1=2,A2=3,{An*An+1}为公比为q=3的等比数列,设 Bn=A2n-1+A2n n为整整数,求证{Bn}为等比数列说明 n n+1 2n-1 2n 为下标](/uploads/image/z/7991041-49-1.jpg?t=%E4%B8%80%E9%81%93%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%E9%A2%98%E5%B7%B2%E7%9F%A5+A1%3D2%2CA2%3D3%2C%7BAn%2AAn%2B1%7D%E4%B8%BA%E5%85%AC%E6%AF%94%E4%B8%BAq%3D3%E7%9A%84%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%2C%E8%AE%BE+Bn%3DA2n-1%2BA2n+n%E4%B8%BA%E6%95%B4%E6%95%B4%E6%95%B0%2C%E6%B1%82%E8%AF%81%7BBn%7D%E4%B8%BA%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%E8%AF%B4%E6%98%8E+n+n%2B1+2n-1+2n+%E4%B8%BA%E4%B8%8B%E6%A0%87)
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