4x+9y=12 3y-2z=1 7x+5z=19/4

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4x+9y=12 3y-2z=1 7x+5z=19/4
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4x+9y=12 3y-2z=1 7x+5z=19/4
4x+9y=12 3y-2z=1 7x+5z=19/4

4x+9y=12 3y-2z=1 7x+5z=19/4
4x+9y=12 .(1)
3y-2z=1 .(2)
7x+5z=19/4 .(3)
(1)-3*(2):4x+6z=9.(4)
(4)*7-(3)*4:22z=44
z=2
代入(4):4x+6*2=9
4x=-3
x=-3/4
z=2代入(2):3y-2*2=1
y=5/3
解为:
x=-3/4
y=5/3
z=2

方程题4道1.4(x-y-1)=3(1-y)+3.5 (x/2)+(y/3)=2 2.2(x-y)/3-(x+y)/4=13/6 6(x+y)-4(2x-y)=16 3.3x-y+z=3 2x+y-3z=9 x+y+z=12 4.5x-4y+4z=13 2x+7y-3z=19 3x+2y-z=18 三元一次方程:x+3y+2z=2 3x-y+2z=3 3x+2y-4z=3 2x+y-3z=11 2x-y=7 x+y+z=12还有:7x+2y-z=76x-y+z=74x+3y+z=9 好了,2x+y-3z=11 2x-y=7x+y+z=12 ..1.x+y+z=26,2.4y+3z=7,y-z=1,3x+2z=17,x+2y-z=18 9x-7y=173.x-7y+3z=17 4.2x+4y+3z=95x-6y-z=24 3x-2y+5z=113x+7y-2z=1 5x-6y+7z=131.x+y+z=26,y-z=1x+2y-z=18 2.4y+3z=7,3x+2z=11,9x-7y=17 3.x-7y+3z=17 5x-6y-z=24 3x+7y-2z=14.2x+4y+3z=93x-2y+5z=11 5x-6y+7z=13 初二数学三元一次方程计算题应用题求解, 3x-y+2z=3 2x+y-3z=11 x+y+z=12 3x-4z=7 2x+3y+z=9 5x-9y+7z=8 y=2x-7 5x+3y+2z 3x-4z=2 2x-y+2z=8 y+2z=-2 3x+y-4z=1x+y-z=11 y+z-x=5 4x+9y=12 3y-2y+5z=11 5x-6y+7z=13 求:x y z等于多少 解三元一次方程组.速回.(1)X+Y+Z=25 X-Y=1 2X+Y-Z=18(2)X-Y-Z=0 X+Y-3Z=4 2X+3Y-5Z=14(3) X-2Y=-9 Y-Z=3 2Z+x=47(4)3X-y+z=4 2X+3Y-Z=12 X+Y+z=-28(5)4X+9Y=13 3y-2Z=-1 7X+5Z=17速回 我会奖励积分 问5道3元一次方程组题目(1) y=2x-7{ 5x+3y+2z=23x-4z=4 (2) 4x+9y=12{3y-2z=17x+5z=19/4(3)4x-9z=17{3x+y+5z=18x+2y+3z=2(4) 2x+4y+3z=9{3x-2y+5z=115x-6y+7z=13(5) x:y=3:2{y:z=5:4x+y+z=66 方程组3x+y-4z=1 2x-y-2z=6 5x+3y-3z= --1/2{负二分之一} x=?y=?z=?3x+2y+z=13 x+y+2z=7 2x+3y-z=12 x=?y=?z=? 六年级三元一次方程组.解下列方程组:(1)5x-3y+z=25x+2y-4z=3-5x+y-z=2(2)x-y-z=-13x_5y+7z=114x-y+2z=-1(3)9x-5y+z=-69x+y+4z=3-9x+3y-5z=0(4)x+y=22x+z=-27y+z=13 3Q一定要有过程.1】 x-2y= ─9 2】3x-y+z=4 3】y=2x-7 4】4x+9x=12 y-z=3 2x+3y-z=12 5x+3y+2z=2 3y-2z=1 2z+x=47 x+y+z=6 3x-4z=4 7x+5z=4/19 4】x:y=3:2 5】x+y+z=26 6】x+y=3 7】x-y-z=2 y:z=5:4 x-y=1 y+z=5 y-z-x= ─5 x+y+z=66 2x-y+z=18 (1)x-2y=-9,y-z=3,2z+x=47.(2)3x-y+z=4,2x+3y-z=12,x+y+z=6.(3)x+2y=4,2x+3x=13,3y+z=6.(4)5x+6y+2z=80,4x-3y+z=16,3x-2y+6z=92.(5)x:y=5:3,x:z=7:2,x-3y+3z=4每个都是方程组,我不会打大括号顺便告诉我方法是什么 (3)的方程打错了 1 已知x+y/y=7/3 求x+y/x-y等于什么2 若x+4/3=y+3/2=z+8/4 且x+y+z=12 求x、y、z的值 三元一次方程组(1)x-2y=-9 y-z=3 2z+x=47 (2)3x-y+z=4 2x+3y-z=12 x+y+z=6 解下列三元一次方程组:(1)x-z=4,x+y-z=-1,2y-z=1 (2)3x+4z=7,2x+3y+z=9,x-y+z=8 {x+y+z=1 {x+3y+7z=2 {x+5y+19z=4 1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38 {5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-1 三元一次方程组,1.x-2y+z=9 2x+y+3z=10 3x+2y1.x-2y+z=92x+y+3z=103x+2y-z2.3x-5y+2z=14x+5y-z=5X-5y+3z=-23.7x+2y-z=76x-y+z=74x+3y+z=94.4x+3y-2z=-75x-6y+z=12x+z=-25.2x+3y-4z=-23x-2y+5z=262x+5z=31