(2sin^2x-sinxcosx+cos^2x)/sin^2x+cos^2x=(2tan^x-tanx+1)/(tan^2x+1)怎么算

cos^2+2sinxcosx+sin^2x sin 2x为何等于2sinxcosx f(x)=sin^2x+sinxcosx-1/2,化简 y=(cos^2x)/(sinxcosx-sin^2x),(0 sin²X-sinxcosx+2cos²x=化简 sin²x+sinxcosx+2cos²x= f(x)=sin^2x+sinxcosx 如何化简 化简cos^4x-2sinxcosx-sin^4x 2sin平方x +cos平方x+3sinxcosx化简 求证 1+2sinxcosx/sin^2x-cos^2x=sin^2x-cos^2x/1-2sinxcosx 证明1-2sinxcosx/cos^2x-sin^2x=cos^2x-sin^2/1+2sinxcosx 2sin^2x-sinxcosx-cos^2=1 2根号3sinxcosx+2sin^2x的值域 求y=sin^2x+2sinxcosx的周期 已知tanx 2 则sin^2x-sinxcosx y=sin^2x+2sinxcosx的值域 y=sin^2x-sinxcosx+1/2的值域 化简(sin^2x+2sinxcosx)/1+tanx