作业帮已知[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求4x÷（4x²-y²）-1÷（2x+y）的值
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![已知[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求4x÷（4x²-y²）-1÷（2x+y）的值](/uploads/image/z/806144-32-4.jpg?t=%E5%B7%B2%E7%9F%A5%5B%28x%26%23178%3B%2By%26%23178%3B%29-%28x-y%29%26%23178%3B%2B2y%28x-y%29%5D%C3%B74y%3D1%2C%E6%B1%824x%C3%B7%EF%BC%884x%26%23178%3B-y%26%23178%3B%EF%BC%89-1%C3%B7%EF%BC%882x%2By%EF%BC%89%E7%9A%84%E5%80%BC)
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已知[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求4x÷（4x²-y²）-1÷（2x+y）的值
已知[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求4x÷（4x²-y²）-1÷（2x+y）的值
已知[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求4x÷（4x²-y²）-1÷（2x+y）的值
[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1
(4xy-2y²)÷4y=1
得 2x-y=2
4x÷(4x²-y²)-1÷(2x+y)=4x÷[(2x-y)(2x+y)]-1÷(2x+y)
=2x÷(2x+y)-1÷(2x+y)
=(2x-1)/(2x+y)
[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1
[x²+y²-(x²-2xy+y²)+2xy-2y²]÷4y=1
[x²+y²-x²+2xy-y²+2xy-2y²]÷4y=1
[4xy-2y²]÷4y=1
x-1/2...
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[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1
[x²+y²-(x²-2xy+y²)+2xy-2y²]÷4y=1
[x²+y²-x²+2xy-y²+2xy-2y²]÷4y=1
[4xy-2y²]÷4y=1
x-1/2y=1
所以2x-y=2
4x÷（4x²-y²）-1÷（2x+y）
=4x/（4x²-y²）-(2x-y)/（4x²-y²）
=(4x-2x+y)/（4x²-y²）
=(2x+y)/(2x+y)(2x-y)
=1/(2x-y)
=1/2
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