作业帮(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)] 其中x=-1(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)] 其中x=-1,y=2
来源：学生作业帮助网 编辑：作业帮 时间：2024/09/09 21:42:51
![(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)] 其中x=-1(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)] 其中x=-1,y=2](/uploads/image/z/806302-46-2.jpg?t=%282x%26%23178%3By-2xy%26%23178%3B%29-%5B%28-3x%26%23178%3By%26%23178%3B%2B3x%26%23178%3By%29%2B%283x%26%23178%3By%26%23178%3B-3xy%26%23178%3B%29%5D+%E5%85%B6%E4%B8%ADx%3D-1%282x%26%23178%3By-2xy%26%23178%3B%29-%5B%28-3x%26%23178%3By%26%23178%3B%2B3x%26%23178%3By%29%2B%283x%26%23178%3By%26%23178%3B-3xy%26%23178%3B%29%5D+%E5%85%B6%E4%B8%ADx%3D-1%2Cy%3D2)
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(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)] 其中x=-1(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)] 其中x=-1,y=2
(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)] 其中x=-1
(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)] 其中x=-1,y=2
(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)] 其中x=-1(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)] 其中x=-1,y=2
