用因式分解法解方程:2(y-1)²+y=1
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用因式分解法解方程:2(y-1)²+y=1
用因式分解法解方程:2(y-1)²+y=1
用因式分解法解方程:2(y-1)²+y=1
2(y-1)²+y=1
2(y-1)²+(y-1)=0
(y-1)(2y-2+1)=0
(y-1)(2y-1)=0
y-1=0或2y-1=0
y1=1 y2=1/2
2(y-1)²+y-1=0
2(y-1)²+(y-1)=0
(y-1)(2y-2+1)=0
(y-1)(2y-1)=0
y=1,y=1/2
(y-1)(2(y-1)+1)=0
(y-1)(2y-1)=0
y=1或y=1/2