x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积
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x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积
x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积
x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积
x^2+y^2=a^2,y^2+z^2=a^2所围体积,考虑对称性,每个卦限体积相等,只要还求出第一卦限体积再乘以8即可,
积分区域Ω,在ZOY平面投影是1/4圆,0≤y≤a,
0≤z≤√(a^2-y^2),
0≤x≤√(a^2-y^2),即下限为x=0的平面(YOZ平面),上限为√(a^2-y^2)的柱面,
V=8∫[0,a]dy∫[0,√(a^2-y^2)]dz∫[0,√(a^2-y^2]dx
=8∫[0,a]dy∫[0,√(a^2-y^2)](√(a^2-y^2)dz
=8∫[0,a] (a^2-y^2)dy
=8(a^2y-y^3/3) [0,a]
=16a^3/3.
x+y+z=12 x-y+z=2 x-z+y+a=90 x+y+a+z=100,求x y z a
用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之(x-z)(y-z)=?第三部分那个是 (y+z-2x)(x-2y+z)分之(x-z)(y-z)
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
(a-b)+(-2a-b)=?(x+y-z)+(x-y+z)-(x-y-z)=?
(x+y-z)^2-(x-y+z)^2=?
(x-y-z)*( )=x^2-(y+z)^2 填空
已知x+y+z=3a,(a≠0,x,y,z不全等).求(x-a)(y-a)+(y-a)(z-a)+(z-a)(x-a)/(x-a)^2+(y-a)^2+(z-a)^2
x+y+z=3a(a不等于0,x,y,z不全相等)求[(x-a)(y-a)+(y-a)(z-a)+(z-a)(x-a)]/[(x-a)^2+(y-a)^2+(z-a)^2]
已知X+Y+Z=3a求(X-a)(Y-a)+(Y-a)(Z-a)+(Z-a)(X-a)/(X-a)2;+(Y-a)2;+(Z-a)2;,a≠0,X,Y,Z不全相等,
分解因式:f(x,y,z)=x^2(y-z)+y^2(z-x)+z^2(x-y)
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
z=ln(x+a^-y^2) 对y求导,
(y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x+z-2y)的值我已经做到这了:设(X-Y)为a (Z-Y)为b (Z-X)为c则原题= (-a*-c)/-(a+b)(b+c)+ab/-(c+b)(a+c)+c*-b/(-a+c)(a+b)
x+2y=3x+2z=4y+z 求x:y:z