【(x+1/2x-2)-(6/x²-1)-(x+3/2x+2)】·(4x²-4/3)
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/16 09:16:50
![【(x+1/2x-2)-(6/x²-1)-(x+3/2x+2)】·(4x²-4/3)](/uploads/image/z/810624-48-4.jpg?t=%E3%80%90%28x%2B1%2F2x-2%EF%BC%89-%EF%BC%886%2Fx%26%23178%3B-1%EF%BC%89-%EF%BC%88x%2B3%2F2x%2B2%29%E3%80%91%C2%B7%EF%BC%884x%26%23178%3B-4%2F3%EF%BC%89)
x){0ABPߨBN{:+Ԕ
-u
"@F&007I*ҧIv6tm4 M}#
]CM]3}022@MRz.lV!r5Xn ЛFpUhl(@0u
̀@A ݁@
【(x+1/2x-2)-(6/x²-1)-(x+3/2x+2)】·(4x²-4/3)
【(x+1/2x-2)-(6/x²-1)-(x+3/2x+2)】·(4x²-4/3)
【(x+1/2x-2)-(6/x²-1)-(x+3/2x+2)】·(4x²-4/3)
=[(x+1)/2(x-1)-6/(x+1)(x-1)-(x+3)/2(x+1)]×4(x+1)(x-1)/3
=(x+1)/2(x-1)×4(x+1)(x-1)/3-6/(x+1)(x-1)×4(x+1)(x-1)/3-(x+3)/2(x+1) ×4(x+1)(x-1)/3
=2(x+1)²/3-8-2(x+3)(x-1)/3
=(2x²+4x+2-2x²-4x+6)/3-8
=8/3-8
=-16/3