因式分解(x²+x)²-8x²-8x+12和 x³-2x+1求数学高手解答,如题.30分别嫌少了可以吗.
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因式分解(x²+x)²-8x²-8x+12和 x³-2x+1求数学高手解答,如题.30分别嫌少了可以吗.
因式分解(x²+x)²-8x²-8x+12和 x³-2x+1求数学高手解答,
如题.30分别嫌少了可以吗.
因式分解(x²+x)²-8x²-8x+12和 x³-2x+1求数学高手解答,如题.30分别嫌少了可以吗.
(x²+x)²-8x²-8x+12=(x^2+x)^2-8(x^2+x)+12
=(x^2+x-2)(x^2+x-6)
=(x+2)(x-1)(x+3)(x-2)
x³-2x+1=x^3-x^2+x^2-x-x+1
=(x-1)(x^2+x-1)
(x²+x)²-8x²-8x+12
=(x²+x)-8(x²+x)+12
=(x²+x-2)(x²+x-6)
=(x-1)(x+2)(x-2)(x+3)
x³-2x+1
=(x³-x)-(x-1)
=x(x²-1)-(x-1)
=x(x-1)(x+1)-(x-1)
=(x-1)(x²+x-1)
(x²+x)²-8x²-8x+12
=(x²+x)²-8(x²+x)²+12
=(x²+x-6)(x²+x-2)
=(x+3)(x-2)(x+2)(x-1)
x³-2x+1
=x³-1-2(x-1)
=(x-1)(x²+x+1)-2(x-1)
=(x-1)(x²+x-1)
(x²+x)²-8x²-8x+12
=(x²+x)²-8(x²+x)+12
=【(x²+x)-2】【(x²+x)-6】
=(x+2)(x-1)(x+3)(x-2)
x³-2x+1
=(x³-x²)+(x²-2x+1)
=x²(x-1)+(x-1)²
=(x-1)(x²+x-1)
(x-1)(x-2)(x+2)(x+3)
(x-1)(x2+x-1)
(x²+x)²-8x²-8x+12=(x+2)*(x-1)*(x+3)*(x-2)此题用换元法,设(x²+x)=t,原式=t^2-8t+12
x³-2x+1=(x-1)(x^2+x-1)此题用配凑发x³-2x+1=x^3+x^2-x-x^2-x+1=(x^3+x^2+x)-(x^2-x-1)
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(x²+x)²-8x²-8x+12=(x+2)*(x-1)*(x+3)*(x-2)此题用换元法,设(x²+x)=t,原式=t^2-8t+12
x³-2x+1=(x-1)(x^2+x-1)此题用配凑发x³-2x+1=x^3+x^2-x-x^2-x+1=(x^3+x^2+x)-(x^2-x-1)
=x*(x^2-x-1)-(x^2-x-1)
=(x-1)(x^2+x-1)
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