x(x+1)^3+x(x+1)^2+x(x+1)+x+1因式分解
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x(x+1)^3+x(x+1)^2+x(x+1)+x+1因式分解
x(x+1)^3+x(x+1)^2+x(x+1)+x+1因式分解
x(x+1)^3+x(x+1)^2+x(x+1)+x+1因式分解
解
x(x+1)³+x(x+1)²+x(x+1)+x+1
=(x+1)[x(x+1)²+x(x+1)+x+1]
=(x+1)(x+1)[x(x+1)+x+1]
=(x+1)²(x+1)(x+1)
=(x+1)^4
=(x+1)[x(x+1)²+x(x+1)+x+1]
=(x+1)²[x(x+1)+x+1]
=(x+1)³(x+1)
=(x+1)的4次方
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