为什么cos(n-1)π=cos(n+1)πcos(n-1)π=cos(n-1+2)π=cos(n+1)π 对吗?
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![为什么cos(n-1)π=cos(n+1)πcos(n-1)π=cos(n-1+2)π=cos(n+1)π 对吗?](/uploads/image/z/8298063-63-3.jpg?t=%E4%B8%BA%E4%BB%80%E4%B9%88cos%28n-1%29%CF%80%3Dcos%28n%2B1%29%CF%80cos%28n-1%29%CF%80%3Dcos%28n-1%2B2%29%CF%80%3Dcos%28n%2B1%29%CF%80++%E5%AF%B9%E5%90%97%3F)
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为什么cos(n-1)π=cos(n+1)πcos(n-1)π=cos(n-1+2)π=cos(n+1)π 对吗?
为什么cos(n-1)π=cos(n+1)π
cos(n-1)π=cos(n-1+2)π=cos(n+1)π 对吗?
为什么cos(n-1)π=cos(n+1)πcos(n-1)π=cos(n-1+2)π=cos(n+1)π 对吗?
不对
n-1不等于n-1+2
为什么cos(n-1)π=cos(n+1)πcos(n-1)π=cos(n-1+2)π=cos(n+1)π 对吗?
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(-1)^n*cosx=cos(x+nπ)
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lim n→∞ n^(3/2)* (n+1)^(1/2)* (1-cos(π/n))=?
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