函数y=√(x²-2x-3)的定义域为A,函数g(x)=√[(x-1)/(5-x)]的定义域为B,则A∩B=
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函数y=√(x²-2x-3)的定义域为A,函数g(x)=√[(x-1)/(5-x)]的定义域为B,则A∩B=
函数y=√(x²-2x-3)的定义域为A,函数g(x)=√[(x-1)/(5-x)]的定义域为B,则A∩B=
函数y=√(x²-2x-3)的定义域为A,函数g(x)=√[(x-1)/(5-x)]的定义域为B,则A∩B=
函数A要求x²-2x-3>=0,即(x-3)(x+1)>=0,即x>=3或x=0,即1