4、如图21,(6分)AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证:EB=FChttp://image.baidu.com/i?ct=503316480&z=0&tn=baiduimagedetail&word=AD%C6%BD%B7%D6%A1%CFBAC%2CDE%A1%CDAB%D3%DAE%2CDF%A1%CDAC%D3%DAF%2C%C7%D2DB%3DDC%2C%C7%F3%D6%A4%3AEB%3DFC

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4、如图21,(6分)AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证:EB=FChttp://image.baidu.com/i?ct=503316480&z=0&tn=baiduimagedetail&word=AD%C6%BD%B7%D6%A1%CFBAC%2CDE%A1%CDAB%D3%DAE%2CDF%A1%CDAC%D3%DAF%2C%C7%D2DB%3DDC%2C%C7%F3%D6%A4%3AEB%3DFC
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4、如图21,(6分)AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证:EB=FChttp://image.baidu.com/i?ct=503316480&z=0&tn=baiduimagedetail&word=AD%C6%BD%B7%D6%A1%CFBAC%2CDE%A1%CDAB%D3%DAE%2CDF%A1%CDAC%D3%DAF%2C%C7%D2DB%3DDC%2C%C7%F3%D6%A4%3AEB%3DFC
4、如图21,(6分)AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证:EB=FC
http://image.baidu.com/i?ct=503316480&z=0&tn=baiduimagedetail&word=AD%C6%BD%B7%D6%A1%CFBAC%2CDE%A1%CDAB%D3%DAE%2CDF%A1%CDAC%D3%DAF%2C%C7%D2DB%3DDC%2C%C7%F3%D6%A4%3AEB%3DFC&in=19388&cl=2&lm=-1&pn=0&rn=1&di=19237015290&ln=1&fr=&ic=0&s=0&se=1&sme=0&tab= 图

4、如图21,(6分)AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证:EB=FChttp://image.baidu.com/i?ct=503316480&z=0&tn=baiduimagedetail&word=AD%C6%BD%B7%D6%A1%CFBAC%2CDE%A1%CDAB%D3%DAE%2CDF%A1%CDAC%D3%DAF%2C%C7%D2DB%3DDC%2C%C7%F3%D6%A4%3AEB%3DFC
因为是角平分线,所以DE=DF,再加上直角和斜边相等的条件,可以得出EBD≌FCD

已知:如图,AD平分∠女BAC,EG//AD 求证:∠AGF=∠AFG 如图,AD‖EG,∠E=∠1.证明:AD平分∠BAC 已知:如图,AD平分∠女BAC,EG//AD 求证:∠AGF=∠AFG 如图,AD平分∠BAC,AD∥EG,试证∠G=∠AFG 如图,已知EG//AD,∠1=∠G,试说明AD平分∠BAC .如图,已知△ABC中,AD平分∠BAC,EF垂直平分AD 求证：∠B=∠CAE 如图,AD平分∠BAC,AD垂直平分BC,DF⊥AB,BG⊥AC,求证DF=CG 初二几何题求解!如图,三角形ABC,AB=6,AC=4,∠BAC=60°,AD平分∠BAC,求AD的长度用初二及以前所学的知识解决,急! 如图,AD平分∠BAC,AE=DE,试说明:ED‖AC 已知：如图,AB=AC,AD平分∠BAC,证明：△ABD≌△ACD. 如图,在△ABC中,AD平分∠BAC,CD⊥AD于D,求证∠ACD>∠B 如图,在三角形ABC中,AD平分∠BAC,CD垂直AD于D求证；∠ACD>∠B 如图,EG⊥BC,AD⊥BC,∠1=∠E,请说明为什么AD平分∠BAC? 如图,已知AD‖CE ,∠E=∠ACE,试说明AD平分∠BAC 如图,AD‖CE,AD平分∠BAC,则∠ACE=∠E,试说明理由 如图,EG⊥BC,AD⊥BC,∠1＝∠E,请说明什么AD平分∠BAC. 已知,如图,AD⊥BC,EN⊥BC,AD平分∠BAC,求证∠E=∠EFA 如图,半圆O的直径AB=10cm,弦AC=6cm,AD平分∠BAC,则AD的长为?