1.如图,AD平行于BC,AB=DC,E为AD中点,且角ABC=角DCB,求证BE=CE 2.如图,在三角形ABC中,AD垂直BC,垂足为D,AB+BD=DC,试说明∠B=2∠C 3.如图,在正方形ABCD中,E,F分别是BC,CD上的点,且角1=45°,试说明BE+DF=EF12注
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![1.如图,AD平行于BC,AB=DC,E为AD中点,且角ABC=角DCB,求证BE=CE 2.如图,在三角形ABC中,AD垂直BC,垂足为D,AB+BD=DC,试说明∠B=2∠C 3.如图,在正方形ABCD中,E,F分别是BC,CD上的点,且角1=45°,试说明BE+DF=EF12注](/uploads/image/z/8351286-6-6.jpg?t=1.%E5%A6%82%E5%9B%BE%2CAD%E5%B9%B3%E8%A1%8C%E4%BA%8EBC%2CAB%3DDC%2CE%E4%B8%BAAD%E4%B8%AD%E7%82%B9%2C%E4%B8%94%E8%A7%92ABC%3D%E8%A7%92DCB%2C%E6%B1%82%E8%AF%81BE%3DCE+2.%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CAD%E5%9E%82%E7%9B%B4BC%2C%E5%9E%82%E8%B6%B3%E4%B8%BAD%2CAB%2BBD%3DDC%2C%E8%AF%95%E8%AF%B4%E6%98%8E%E2%88%A0B%3D2%E2%88%A0C++++++++3.%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E4%B8%AD%2CE%2CF%E5%88%86%E5%88%AB%E6%98%AFBC%2CCD%E4%B8%8A%E7%9A%84%E7%82%B9%2C%E4%B8%94%E8%A7%921%3D45%C2%B0%2C%E8%AF%95%E8%AF%B4%E6%98%8EBE%2BDF%3DEF12%E6%B3%A8)
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