作业帮先化简再求值：t/(t+1)-(t²-1)/【(t+2)²-1】*(t+3)/(t+1),其中t=（根号2）-1
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/25 13:23:04
x){gu
OzmlzڰY%%چ%jʆֺ& 4a"&j5!jun{cm= |ڿN]C"}[_`gC'a X-D.XD
6r+pDb SU 0DDk {J0"7/.H̳
ZTQYYV
z&T=]t t>ٵ钕[=7N"i
先化简再求值：t/(t+1)-(t²-1)/【(t+2)²-1】*(t+3)/(t+1),其中t=（根号2）-1
先化简再求值：t/(t+1)-(t²-1)/【(t+2)²-1】*(t+3)/(t+1),其中t=（根号2）-1
先化简再求值：t/(t+1)-(t²-1)/【(t+2)²-1】*(t+3)/(t+1),其中t=（根号2）-1
t/(t+1)-(t²-1)/【(t+2)²-1】*(t+3)/(t+1)
=t/(t+1-(t+1)(t-1)/(t+2+1)(t+2-1)x(t+3)/(t+1)
=t/(t+1)-(t+1)(t-1)/(t+3)(t+1)x(t+3)/(t+1)
=t/(t+1)-(t-1)/(t+1)
=1/(t+1)
=1/[(根号2）-1+1]
=(根号2)/2
ertff.hyytfufuf.34
如图又有人天然果然果然