动点P到定点F(根号2,0)的距离与点P到定直线L:X=2倍根号2的距离之比为根号2\2,求动点P的轨迹C的方程?P(x,y)为什么则有下面这个式子?√[(x-√2)²+y²]=|x-2√2|*√2/2
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![动点P到定点F(根号2,0)的距离与点P到定直线L:X=2倍根号2的距离之比为根号2\2,求动点P的轨迹C的方程?P(x,y)为什么则有下面这个式子?√[(x-√2)²+y²]=|x-2√2|*√2/2](/uploads/image/z/8437904-8-4.jpg?t=%E5%8A%A8%E7%82%B9P%E5%88%B0%E5%AE%9A%E7%82%B9F%EF%BC%88%E6%A0%B9%E5%8F%B72%2C0%EF%BC%89%E7%9A%84%E8%B7%9D%E7%A6%BB%E4%B8%8E%E7%82%B9P%E5%88%B0%E5%AE%9A%E7%9B%B4%E7%BA%BFL%3AX%3D2%E5%80%8D%E6%A0%B9%E5%8F%B72%E7%9A%84%E8%B7%9D%E7%A6%BB%E4%B9%8B%E6%AF%94%E4%B8%BA%E6%A0%B9%E5%8F%B72%5C2%2C%E6%B1%82%E5%8A%A8%E7%82%B9P%E7%9A%84%E8%BD%A8%E8%BF%B9C%E7%9A%84%E6%96%B9%E7%A8%8B%3FP%28x%2Cy%29%E4%B8%BA%E4%BB%80%E4%B9%88%E5%88%99%E6%9C%89%E4%B8%8B%E9%9D%A2%E8%BF%99%E4%B8%AA%E5%BC%8F%E5%AD%90%3F%E2%88%9A%5B%28x-%E2%88%9A2%29%26%23178%3B%2By%26%23178%3B%5D%3D%7Cx-2%E2%88%9A2%7C%2A%E2%88%9A2%2F2)
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动点P到定点F(根号2,0)的距离与点P到定直线L:X=2倍根号2的距离之比为根号2\2,求动点P的轨迹C的方程?P(x,y)为什么则有下面这个式子?√[(x-√2)²+y²]=|x-2√2|*√2/2
动点P到定点F(根号2,0)的距离与点P到定直线L:X=2倍根号2的距离之比为根号2\2,求动点P的轨迹C的方程?
P(x,y)为什么则有下面这个式子?
√[(x-√2)²+y²]=|x-2√2|*√2/2
动点P到定点F(根号2,0)的距离与点P到定直线L:X=2倍根号2的距离之比为根号2\2,求动点P的轨迹C的方程?P(x,y)为什么则有下面这个式子?√[(x-√2)²+y²]=|x-2√2|*√2/2
首先两点间距离公式得:√[﹙x-√2﹚²+y²]
到直线的距离:[x-2√2]
由题意得:√[﹙x-√2﹚²+y²]/[x-2√2]=√2/2
所以就得:√[(x-√2)²+y²]=|x-2√2|*√2/2