log以(2x²=1)为底以(3x²+2x-1)为对数=1 求出x log以(2x²+1)为底以(3x²+2x-1)为对数=1

log以(2x²=1)为底以(3x²+2x-1)为对数=1 求出x log以(2x²+1)为底以(3x²+2x-1)为对数=1
log以(2x²=1)为底以(3x²+2x-1)为对数=1 求出x
log以(2x²+1)为底以(3x²+2x-1)为对数=1

log以(2x²=1)为底以(3x²+2x-1)为对数=1 求出x log以(2x²+1)为底以(3x²+2x-1)为对数=1
对数有意义,2x²+1>0,3x²+2x-1>0
2x²+1>0,x可取任意实数.
3x²+2x-1>0
(x+1)(3x-1)>0
x>1/3或x1/3或x

(2x²+1)=(3x²+2x-1)
x^2+2x-2=0
x1=-1+根号3
x2=-1-根号3

请把题写清楚

3x²+2x-1=2x²+1
x²+2x=2
x²+2x+1=3
(x+1)²=3
∴x=-1+√3 x=-1-√3