设Z=e^xy COS(xy),求dz|(0,1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/18 09:24:22
x1n0E-CrfKСh]R#^HS\%@/;EQJ#-z?$o]ج .{o_esot;XQQL`Yy~1W
设Z=e^xy COS(xy),求dz|(0,1)
设Z=e^xy COS(xy),求dz|(0,1)
设Z=e^xy COS(xy),求dz|(0,1)
dZ = эZ/эx *dx + эz/эy*dy
= y*e^(xy)*cos(xy)*dx + e^(xy)*[-ysin(xy)]*dx
+ x*e^(xy)*cos(xy)*dy + e^(xy)*[-xsin(xy)*dy
dZ|(0,1) = 1*e^0*cos0*dx - e^0*y*sin0*dx +0*e^0*cos0*dy - e^0*0*sin0*dy
= dx
z=e^xycosxy
z'x=(1+y')e^xycosxy-(1+y')e^xysinxy
z'y=(1+x')e^xycosxy-(1+x')e^xysinxy
dz=z'x dx+z'ydy
dz|(0,1)=(1+y')dx+(1+x')dy
=dx+(dy/dx)dx+(1+dx/dy)dy
=2dx+2dy
设Z=e^xy COS(xy),求dz|(0,1)
设z=(x+2y)e^xy,求dz
设z=|xy|,求dz
设函数z=f(x,y)由方程e^z=xyz+cos(xy)求dz/dx ,dz/dy.求详解
设z=e^xy,则dz=?
设z=e^xy,则dz|(1,1)=
设z=e^xy,则dz|(1,1)=
求函数z=e^xy*cos(x+y)的全微分dz
设z=arctan(xy),y=e^x ,求dz/dx .
二元函数 设z=(x平方-y平方)e的xy次方,求dz
设z=f(2x+3y,e^xy),求dz
设z=f(xy,e^x+y),求dz高数计算题,坐等大侠
设z=(x+y)^xy,求dz
z=e的xy次方求dz
设方程xz+yz+xy=e的定函数z=z(x,y),求dz
设Z=f(x^2 +y,2xy),求dz/dx和dz/dy
z=xe^xy,求dz
急求“设函数z=xe^(-xy)+sin(xy),则dz=”这道题的做法,