方程x²-(k+1)x+0.25k²+1=0的两根之积为5,求k的值.
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![方程x²-(k+1)x+0.25k²+1=0的两根之积为5,求k的值.](/uploads/image/z/8560221-69-1.jpg?t=%E6%96%B9%E7%A8%8Bx%26%23178%3B-%28k%2B1%29x%2B0.25k%26%23178%3B%2B1%3D0%E7%9A%84%E4%B8%A4%E6%A0%B9%E4%B9%8B%E7%A7%AF%E4%B8%BA5%2C%E6%B1%82k%E7%9A%84%E5%80%BC.)
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方程x²-(k+1)x+0.25k²+1=0的两根之积为5,求k的值.
方程x²-(k+1)x+0.25k²+1=0的两根之积为5,求k的值.
方程x²-(k+1)x+0.25k²+1=0的两根之积为5,求k的值.
根据韦达定理得
x1x2=0.25k²+1=5
得k=4,-4(若在实数范围内,则k=-4舍去)