已知集合A={(x,y)|(y-3)/(x-2)=1},B={(x,y)|y=ax+2},若A∩B=Φ,求实数a的值答案是a=1或a=0.5
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![已知集合A={(x,y)|(y-3)/(x-2)=1},B={(x,y)|y=ax+2},若A∩B=Φ,求实数a的值答案是a=1或a=0.5](/uploads/image/z/8560522-10-2.jpg?t=%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88A%3D%7B%28x%2Cy%29%7C%28y-3%29%2F%28x-2%29%3D1%7D%2CB%3D%7B%28x%2Cy%29%7Cy%3Dax%2B2%7D%2C%E8%8B%A5A%E2%88%A9B%3D%CE%A6%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%80%BC%E7%AD%94%E6%A1%88%E6%98%AFa%3D1%E6%88%96a%3D0.5)
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已知集合A={(x,y)|(y-3)/(x-2)=1},B={(x,y)|y=ax+2},若A∩B=Φ,求实数a的值答案是a=1或a=0.5
已知集合A={(x,y)|(y-3)/(x-2)=1},B={(x,y)|y=ax+2},若A∩B=Φ,求实数a的值
答案是a=1或a=0.5
已知集合A={(x,y)|(y-3)/(x-2)=1},B={(x,y)|y=ax+2},若A∩B=Φ,求实数a的值答案是a=1或a=0.5
A={(x,y)|(y-3)/(x-2)=1}={(x,y)|y=x+1,x≠2},B={(x,y)|y=ax+2}
A∩B=Φ说明y=x+1与y=ax+2平行或A=Φ
若y=x+1与y=ax+2平行
则a=1
A=Φ
则(2,3)不在A中却在B中
则2a+2=3
所以a=1/2
所以a=1/2或1
a=0或1或1/2。用数形结合很快的。