已知函数f(x)=(x^2+ax-2a-3)*e^(3-x),a∈R (1)讨论f(x)的单调性 (2)设g(x)=(a^2+25/4)*e^x,(a>0),若存在x1,x2∈[0,4]使得|f(x1)-g(x2)|
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![已知函数f(x)=(x^2+ax-2a-3)*e^(3-x),a∈R (1)讨论f(x)的单调性 (2)设g(x)=(a^2+25/4)*e^x,(a>0),若存在x1,x2∈[0,4]使得|f(x1)-g(x2)|](/uploads/image/z/8561039-23-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D%28x%5E2%2Bax-2a-3%29%2Ae%5E%283-x%29%2Ca%E2%88%88R+%281%29%E8%AE%A8%E8%AE%BAf%28x%29%E7%9A%84%E5%8D%95%E8%B0%83%E6%80%A7+%282%29%E8%AE%BEg%28x%29%3D%28a%5E2%2B25%2F4%29%2Ae%5Ex%2C%28a%3E0%29%2C%E8%8B%A5%E5%AD%98%E5%9C%A8x1%2Cx2%E2%88%88%5B0%2C4%5D%E4%BD%BF%E5%BE%97%7Cf%28x1%29-g%28x2%29%7C)
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