已知a=99b=0.03求ab+a-b-1/a2b2-a2-b2+1的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 09:58:29
已知a=99b=0.03求ab+a-b-1/a2b2-a2-b2+1的值
x){}Km--l mlJLNM5O4J2M4M26|>i"}RِeVymtF.ՏNTS64Hк`)8; X#($gBeP{'Cܬr }6IjjXZj#̰4/.H̳́jݏU! X4h\LK ~E i

已知a=99b=0.03求ab+a-b-1/a2b2-a2-b2+1的值
已知a=99b=0.03求ab+a-b-1/a2b2-a2-b2+1的值

已知a=99b=0.03求ab+a-b-1/a2b2-a2-b2+1的值
ab+a-b-1/a2b2-a2-b2+1
=[a(b+1)-(b+1)]/[a²(b²-1)-(b²-1)]
=(b+1)(a-1)/(b²-1)(a²-1)
=1/(b-1)(a+1)
当b=0.03 a=99时
原式=1/(1-0.03)(99+1)
=1/97

原式=[a(b+1)-(b+1)]/[a²(b²-1)-(b²-1)]
=(b+1)(a-1)/[(b²-1)(a²-1)]
=(b+1)(a-1)/[(b+1)(b-1)(a+1)(a-1)]
=1/[(b-1)(a+1)]
=1/(-0.97×100)
=-1/97