o为三角形ABC的外心,CO的延长线交圆与F,AD垂直BC,BE垂直AC,AD交BE于H,M为BC中点,求证:OM=1/2*AH
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![o为三角形ABC的外心,CO的延长线交圆与F,AD垂直BC,BE垂直AC,AD交BE于H,M为BC中点,求证:OM=1/2*AH](/uploads/image/z/8574669-45-9.jpg?t=o%E4%B8%BA%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E5%A4%96%E5%BF%83%2CCO%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4%E5%9C%86%E4%B8%8EF%2CAD%E5%9E%82%E7%9B%B4BC%2CBE%E5%9E%82%E7%9B%B4AC%2CAD%E4%BA%A4BE%E4%BA%8EH%2CM%E4%B8%BABC%E4%B8%AD%E7%82%B9%2C%E6%B1%82%E8%AF%81%EF%BC%9AOM%3D1%2F2%2AAH)
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