已知根号3sinα+cosα=2根号3/3,则cos(2α+π/3)=
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已知根号3sinα+cosα=2根号3/3,则cos(2α+π/3)=
已知根号3sinα+cosα=2根号3/3,则cos(2α+π/3)=
已知根号3sinα+cosα=2根号3/3,则cos(2α+π/3)=
已知:√3sinα+cosα=2√3/3,则:√3/2*sinα+1/2*cosα=√3/3=cos(π/6)*sinα+sin(π/6)*cosα
=sin(α+π/6)=√3/3;则:[sin(α+π/6)]^2=1/3
因为:cos(2α+π/3)=cos2(α+π/6)=1-2[(sin(α+π/6)]^2=1-2*1/3=1-2/3=1/3