求1+2+2^2+2^3+…+2^2012的值,可令S=1+2+2^2+2^3+…+2^2012,则2S=2+2^2+2^3+2^4+…+2^2012+2^2013,因此2S-S=2^2013-1.仿照以上推理,计算出1+5+5^2+5^3+…+5^2012的值为?怎么算呢?
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![求1+2+2^2+2^3+…+2^2012的值,可令S=1+2+2^2+2^3+…+2^2012,则2S=2+2^2+2^3+2^4+…+2^2012+2^2013,因此2S-S=2^2013-1.仿照以上推理,计算出1+5+5^2+5^3+…+5^2012的值为?怎么算呢?](/uploads/image/z/8583215-23-5.jpg?t=%E6%B1%821%2B2%2B2%5E2%2B2%5E3%2B%E2%80%A6%2B2%5E2012%E7%9A%84%E5%80%BC%2C%E5%8F%AF%E4%BB%A4S%3D1%2B2%2B2%5E2%2B2%5E3%2B%E2%80%A6%2B2%5E2012%2C%E5%88%992S%3D2%2B2%5E2%2B2%5E3%2B2%5E4%2B%E2%80%A6%2B2%5E2012%2B2%5E2013%2C%E5%9B%A0%E6%AD%A42S-S%3D2%5E2013-1.%E4%BB%BF%E7%85%A7%E4%BB%A5%E4%B8%8A%E6%8E%A8%E7%90%86%2C%E8%AE%A1%E7%AE%97%E5%87%BA1%2B5%2B5%5E2%2B5%5E3%2B%E2%80%A6%2B5%5E2012%E7%9A%84%E5%80%BC%E4%B8%BA%3F%E6%80%8E%E4%B9%88%E7%AE%97%E5%91%A2%3F)
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