若g(x)=x^2+ax+b,则g[(x1+x2)/2]≤[g(x1)+g(x2)]/2麻烦用张纸解出来,因为用电脑表达的不是很清楚
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若g(x)=x^2+ax+b,则g[(x1+x2)/2]≤[g(x1)+g(x2)]/2麻烦用张纸解出来,因为用电脑表达的不是很清楚
若g(x)=x^2+ax+b,则g[(x1+x2)/2]≤[g(x1)+g(x2)]/2
麻烦用张纸解出来,因为用电脑表达的不是很清楚
若g(x)=x^2+ax+b,则g[(x1+x2)/2]≤[g(x1)+g(x2)]/2麻烦用张纸解出来,因为用电脑表达的不是很清楚
[g(x1)+g(x2)]/2=[x1²+x2²+a(x1+x2)+2b]/2=(x1²+x2²)/2+a(x1+x2)/2+b
g[(x1+x2)/2]=(x1+x2)²/4+a(x1+x2)/2+b
∴g[(x1+x2)/2]-[g(x1)+g(x2)]/2
=(x1+x2)²/4-(x1²+x2²)/2
=(x1²+2x1x2+x2²-2x1²-2x2²)/4
=-(x1-x2)²/4≤0
∴g[(X1+X2)/2]≤[g(x1)+g(x2)]/2有点懒 求采纳 谢谢