C语言答案为什么是8 4 #includevoid f(int y,int x){y=y+x;x=x+y;}main(){int x=2,y=4;f(y,&x);printf("%d %d\n",x,y);}

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C语言答案为什么是8 4 #includevoid f(int y,int *x){y=y+*x;*x=*x+y;}main(){int x=2,y=4;f(y,&x);printf("%d %d\n",x,y);}
C语言答案为什么是8 4
#include
void f(int y,int *x)
{y=y+*x;
*x=*x+y;
}
main()
{int x=2,y=4;
f(y,&x);
printf("%d %d\n",x,y);
}

C语言答案为什么是8 4 #includevoid f(int y,int *x){y=y+*x;*x=*x+y;}main(){int x=2,y=4;f(y,&x);printf("%d %d\n",x,y);}
f(y,&x); => function f
因为y没有修改原内存内容,所以没有修改,而x因为用指针修改了原内容,所以等同于在原函数x+=y.

C语言 答案为什么是8 4 #includevoid f(int y,int *x){y=y+*x;*x=*x+y;}main(){int x=2,y=4;f(y,&x);printf("%d %d\n",x,y);}

C语言答案为什么是8 4 #includevoid f(int y,int x){y=y+x;x=x+y;}main(){int x=2,y=4;f(y,&x);printf("%d %d\n",x,y);}