作业帮sin(π/12)-cos(π/12)=
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sin(π/12)-cos(π/12)=
sin(π/12)-cos(π/12)=
sin(π/12)-cos(π/12)=
0
[sin(π/12)-cos(π/12)]²
=sin²(π/12)-2sin(π/12)cos(π/12)+cos²(π/12)
=1-sin(π/6)
=1/2
∵sin(π/12)
sin(π/12)-cos(π/12)=√2[sin(π/12)(√2/2)-(√2/2)cos(π/12)]
=√2[sin(π/12)cos(π/4)-cos(π/12)sin(π/4)]
=√2sin[(π/12)-(π/4)]
=√2sin(-π/6)
=-√2/2