作业帮已知:x-2y+3=0 求x^2-(4y+1)x+4y^2+2y
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已知:x-2y+3=0 求x^2-(4y+1)x+4y^2+2y
已知:x-2y+3=0 求x^2-(4y+1)x+4y^2+2y
已知:x-2y+3=0 求x^2-(4y+1)x+4y^2+2y
由x-2y+3=0得x-2y=-3
x^2-(4y+1)x+4y^2+2y
=x^2-4xy+4y^2-x+2y
=(x-2y)^2-(x-2y)
=(-3)^2+3
=12
x^2-(4y+1)x+4y^2+2y.
=x^2-4xy-x+4y^2+2y
=(x^2-4xy+4y^2)-(x-2y)
=(x-2y)^2-(x-2y)
=(-3)^2-(-3)
=12
(x-2y)平方-（x-2y）=9+3=12
注x-2y+3=0知：x-2y=-3
-
x-2y=-3
x^2-(4y+1)x+4y^2+2y
=(x^2-4xy+4y^2)-x+2y
=(x-2y)^2-(x-2y)
=(-3)^2-(-3)
=9+3
=12
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