设p=2a-1,q=1/3a+3,且2p=3q+1,求3a*3a-[7a*7a-2(a*a+2a)]

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 15:26:33
设p=2a-1,q=1/3a+3,且2p=3q+1,求3a*3a-[7a*7a-2(a*a+2a)]
xAJAE$b63b\D@z!Ft!Z!d&^fz\D\ꪪ>OW>v&TTI^[B1\g,2`I(;N;.

设p=2a-1,q=1/3a+3,且2p=3q+1,求3a*3a-[7a*7a-2(a*a+2a)]
设p=2a-1,q=1/3a+3,且2p=3q+1,求3a*3a-[7a*7a-2(a*a+2a)]

设p=2a-1,q=1/3a+3,且2p=3q+1,求3a*3a-[7a*7a-2(a*a+2a)]
把 p和q代进去,即2(2a-1)=3(1/3a+3)+1
a=4
原式=12*12-(28*28-2a²-4a)
=144-(784-32-16)
=144-784+32+16
= -592

a=4,答案为:-592