设p=2a-1,q=1/3a+3,且2p=3q+1,求3a*3a-[7a*7a-2(a*a+2a)]
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设p=2a-1,q=1/3a+3,且2p=3q+1,求3a*3a-[7a*7a-2(a*a+2a)]
设p=2a-1,q=1/3a+3,且2p=3q+1,求3a*3a-[7a*7a-2(a*a+2a)]
设p=2a-1,q=1/3a+3,且2p=3q+1,求3a*3a-[7a*7a-2(a*a+2a)]
把 p和q代进去,即2(2a-1)=3(1/3a+3)+1
a=4
原式=12*12-(28*28-2a²-4a)
=144-(784-32-16)
=144-784+32+16
= -592
a=4,答案为:-592