1/(2/3)/(3/4)/(4/5)/./(2002/2003)/(2003/2004)

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1/(2/3)/(3/4)/(4/5)/./(2002/2003)/(2003/2004)
x)30707&z@1#} Q MR>: lȱPKAd \* 6yvPl3

1/(2/3)/(3/4)/(4/5)/./(2002/2003)/(2003/2004)
1/(2/3)/(3/4)/(4/5)/./(2002/2003)/(2003/2004)

1/(2/3)/(3/4)/(4/5)/./(2002/2003)/(2003/2004)
=1* 3/2*...*2004/2003
=2004/2
=1002

除一个数 就是乘以它的倒数 写出来 就容易发现规律 1002
3 4 2004 约掉为1 2004 2004
1*——*——*.......*———— = 1*————* ————=——=1002
2 3 2003 2 约掉为1 2